Exponential functions and growth

College Algebra. Also known as: math 101, math 1314, math 1111, math 110, mat 140, intermediate algebra, precalculus i, algebra for college students, math 1010, college algebra and trigonometry

Model repeated percentage growth and decay with f(x) = a·bˣ, including compound interest and half-life.

The idea

In an exponential function the variable is in the exponent: f(x) = a·bˣ, with b > 0 and b ≠ 1. The number a is the starting value (the y-intercept, since b⁰ = 1) and b is the growth factor per step.

  • If b > 1 the function grows.
  • If 0 < b < 1 it decays.

A growth rate r gives b = 1 + r; a decay rate r gives b = 1 − r. So 6% growth means b = 1.06 and 10% decay means b = 0.9.

The graph

For b > 1, the graph rises steeply to the right and flattens toward the x-axis on the left. The x-axis (y = 0) is a horizontal asymptote. The domain is all real numbers; the range is y > 0. Adding a constant shifts the asymptote: f(x) = 2ˣ + 3 has asymptote y = 3.

Solving simple exponential equations

If both sides can be written with the same base, set the exponents equal. For 5^(x + 1) = 125, write 125 = 5³, so x + 1 = 3 and x = 2. For 2ˣ = 32, note that 32 = 2⁵, so x = 5. If the bases cannot be matched, you need logarithms (next topic).

Compound interest

If P is invested at annual rate r, compounded n times per year, after t years:

A = P(1 + r/n)^(nt)

For yearly compounding this is A = P(1 + r)^t.

Worked example

You invest $2,000 at 5% compounded annually. What is it worth after 3 years?

  • A = 2000(1.05)³
  • 1.05³ = 1.157625
  • A = 2000 × 1.157625 = $2,315.25

Compare with simple interest, which would give 2000 + 3(100) = $2,300. Compounding earns interest on interest, so it is larger.

Doubling and half-life

A quantity that doubles every 5 days from 4 units is 4 × 2^(t/5). At t = 15 that is 4 × 2³ = 32.

Decay works the same way with a factor of 1/2 per half-life. An 80 mg sample with a 3-day half-life has 40 mg after 3 days, 20 after 6, and 10 mg after 9 days. In general amount = 80 × (1/2)^(t/3).

Continuous growth

When compounding is continuous, A = Peʳᵗ, where e ≈ 2.718 is a special constant. It appears in many science models.

Common mistakes

  • Using b = r instead of b = 1 + r. A 6% rise is 1.06, not 0.06.
  • Rounding the factor too early. Keep extra digits until the end.
  • Confusing a linear model (adds the same amount) with an exponential one (multiplies by the same factor).

Practice questions

  1. Solve 2ˣ = 32.

  2. Solve 5^(x + 1) = 125.

  3. What does y = 1000(0.9)ᵗ describe?

  4. What is $100 worth after 2 years at 8% compounded annually?

  5. What is the horizontal asymptote of f(x) = 2ˣ + 3?

  6. A culture starts at 4 units and doubles every 5 days. How many units after 15 days?

Exponential functions and growth explained: College Algebra study guide | CoLabEx