Polynomial functions

College Algebra. Also known as: math 101, math 1314, math 1111, math 110, mat 140, intermediate algebra, precalculus i, algebra for college students, math 1010, college algebra and trigonometry

Find zeros, factors and end behaviour of polynomials using the remainder and factor theorems.

What is a polynomial function?

A polynomial is a sum of terms like a·xⁿ with whole-number powers, such as f(x) = x³ − 2x² − 5x + 6. The degree is the highest power and the leading coefficient is the number in front of it.

End behaviour

Far to the left and right, only the leading term matters:

  • Even degree, positive leading coefficient: both ends rise.
  • Even degree, negative leading coefficient: both ends fall.
  • Odd degree, positive leading coefficient: falls on the left, rises on the right.
  • Odd degree, negative leading coefficient: rises on the left, falls on the right.

A polynomial of degree n has at most n real zeros and at most n − 1 turning points.

Zeros, factors and multiplicity

A zero (or root) is an x-value where f(x) = 0, which is where the graph meets the x-axis. The Factor Theorem says: x − c is a factor of f(x) exactly when f(c) = 0.

The Remainder Theorem says that dividing f(x) by x − c leaves remainder f(c). So you can find a remainder just by evaluating.

Multiplicity counts how many times a factor repeats. In f(x) = (x − 1)²(x + 4) the zero x = 1 has multiplicity 2: the graph touches the axis and turns back. A zero of multiplicity 1 is crossed straight through.

Rational zero test

If f has whole-number coefficients, any rational zero p/q has p dividing the constant term and q dividing the leading coefficient. For 2x³ − 5x + 3, p comes from ±1, ±3 and q from ±1, ±2, so candidates include ±1, ±3, ±1/2, ±3/2.

Worked example

Find all zeros of f(x) = x³ − 2x² − 5x + 6.

  1. Test candidates from ±1, ±2, ±3, ±6. f(1) = 1 − 2 − 5 + 6 = 0, so x − 1 is a factor.
  2. Divide by x − 1 (long or synthetic division) to get x² − x − 6.
  3. Factor: x² − x − 6 = (x − 3)(x + 2).
  4. So f(x) = (x − 1)(x − 3)(x + 2) and the zeros are 1, 3 and −2.

The y-intercept is f(0) = 6, which matches the product of the constants: (−1)(−3)(2) = 6.

Sketching

Plot the zeros, mark the y-intercept, decide crossing or touching from multiplicity, and make the ends match the end behaviour. Here the degree is 3 with a positive leading coefficient, so the graph rises on the right and falls on the left.

Common mistakes

  • Using f(−c) instead of f(c) for the factor x − c. (For x + 3, test c = −3.)
  • Forgetting that missing terms need a zero placeholder in synthetic division.
  • Assuming a degree-n polynomial always has n real zeros; some are complex.

Practice questions

  1. What is the end behaviour of f(x) = −2x⁴ + x?

  2. What is the remainder when x³ + 2x − 5 is divided by x − 2?

  3. Which is a factor of x² + x − 6?

  4. At the zero x = 1 of f(x) = (x − 1)²(x + 4), the graph…

  5. What is the most turning points a degree 5 polynomial can have?

  6. Which could be a rational zero of 2x³ − 5x + 3?

Polynomial functions explained: College Algebra study guide | CoLabEx