Gases

General Chemistry I. Also known as: chem 101, chem 1411, chem 1311, chem 111, chem 1a, chemistry 101, chemistry 1, general chemistry, general chemistry 1, gen chem 1, general chemistry i, intro chemistry

The gas laws, the ideal gas equation, partial pressures, effusion and the kinetic molecular theory.

Describing a gas

A gas is described by four variables: pressure P, volume V, temperature T and amount n. Pressure units include atmospheres (atm), kilopascals and millimetres of mercury, with 1 atm = 101.325 kPa = 760 mmHg. In every gas law the temperature must be in kelvin; using degrees Celsius is the most common error in this topic.

The individual laws

  • Boyle's law: at constant n and T, P × V is constant, so P1 V1 = P2 V2.
  • Charles's law: at constant n and P, V / T is constant.
  • Avogadro's law: at constant P and T, volume is proportional to moles.
  • Combined gas law: P1 V1 / T1 = P2 V2 / T2 when the amount is fixed.

The ideal gas equation

Combining them gives PV = nRT. With pressure in atm and volume in litres, R = 0.08206 L·atm/(mol·K). Rearranged for density d = mass/V, the molar mass is M = dRT / P. At 273.15 K and 1 atm (the definition of standard temperature and pressure used here) one mole of ideal gas occupies about 22.41 L.

Mixtures and motion

Dalton's law: the total pressure is the sum of partial pressures, and each gas's partial pressure is its mole fraction times the total, P_A = x_A P_total. Graham's law: the rate of effusion is inversely proportional to the square root of molar mass, so lighter gases escape faster: rate1 / rate2 = sqrt(M2 / M1).

The kinetic molecular theory explains these laws by picturing tiny particles in constant random motion, far apart, with no attractions. The average kinetic energy is proportional to absolute temperature only: doubling T in kelvin doubles the average energy. Real gases deviate from ideality at high pressure (particle volume matters) and low temperature (attractions matter).

Worked example

A rigid 5.00 L tank holds 0.250 mol of an ideal gas at 310 K. Find the pressure, then the pressure if the tank is cooled to 155 K.

  1. P = nRT / V = (0.250)(0.08206)(310) / 5.00 = 1.27 atm.
  2. Because n and V stay fixed, pressure is proportional to T. Halving the kelvin temperature from 310 K to 155 K halves the pressure: 1.27 / 2 = 0.636 atm.
  3. Check with the gas law: (0.250)(0.08206)(155) / 5.00 = 0.636 atm. It agrees.

Notice that if you had halved the Celsius temperature instead (37 °C to 18.5 °C), you would have found an answer that is far too large. Whenever a problem lists a temperature in °C, convert first by adding 273.15, then solve.

Practice questions

  1. A gas at 2.0 atm occupies 3.0 L. If the temperature and amount are fixed and the volume is expanded to 6.0 L, what is the new pressure?

  2. A fixed amount of gas at constant pressure has a volume of 2.00 L at 27 °C. What is its volume at 177 °C?

  3. Using R = 0.08206 L·atm/(mol·K), how many moles of ideal gas are in 2.00 L at 1.50 atm and 300. K?

  4. An ideal gas has a density of 1.96 g/L at 1.00 atm and 273.15 K. Using R = 0.08206 L·atm/(mol·K), its molar mass is…

  5. A flask holds 0.40 mol N2 and 0.10 mol O2 at a total pressure of 2.0 atm. What is the partial pressure of N2?

  6. For 2 KClO3 → 2 KCl + 3 O2, what volume of O2 (ideal, 273.15 K and 1 atm, 22.41 L/mol) forms from 0.50 mol KClO3?

Full reading: Chemistry 2e (OpenStax), licence Creative Commons Attribution-NonCommercial-ShareAlike (CC BY-NC-SA). Explanations and questions on this page were written by CoLabEx; no text is copied from the book.

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Gases explained: General Chemistry I study guide | CoLabEx